Dr Gulshan S. answered • 01/27/17

Tutor

4.9
(45)
PhD In Physics and experience of teaching IB Physics and Math High sc

A= 58, B = 36 and C =40 units

Ax =A cos 42

Bx = - B Cos 59 ( as this acts in –ve X direction ) as 180- 121 = 59

Cx = C Cos 53

Now Y components

Ay =A Sin 42

By = B Sin 59

Cy = C Sin 53

Net X component = Ax + Bx +Cx = 58 Cos 42 - 36 Cos 59 + 40 Cos 53 = Rx

( Here 59 has come as 180 -121 = 59 is in – X direction)

Net Y component = Ay +By +Cy = 58 Sin 42 + 36 Sin 59 + 40 Sin 53 =Ry

Hence the resultant

R = ( Rx

^{2}+Ry

^{2})

^{1/2}